In an ap the sum of the first 10 terms
WebApr 8, 2024 · Given sum of first ten terms = − 150 We know that Sum of n terms of AP S n = n 2 [ 2 a + ( n − 1) d] Therefore, ⇒ S 10 = 10 2 [ 2 a + ( 10 − 1) d] ⇒ − 150 = 5 [ 2 a + 9 d] ⇒ … WebQuestion: in an AP of 50 terms ,the sum of first 10 terms is 210 and the sum of its last 15 terms is 2565 find the AP. in an AP of 50 terms ,the sum of first 10 terms is 210 and the …
In an ap the sum of the first 10 terms
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WebFeb 17, 2024 · in an AP the sum of first 10 terms is -150 and the sum of its next 10 terms is -550 find the AP Asked by Keerthandiwakar19 17 Feb, 2024, 01:07: PM Expert Answer Let a be the first term and d be the common difference of A.P. Sum of first 10 terms = -150 hence we have (10/2) [ 2a + 9d ] = -150 or 2a + 9d = -30 ..................... (1)
WebFinding number of terms when sum of an arithmetic progression is given. Google Classroom. The sum of n n terms of an arithmetic sequence is 203 203. The first term is 20 20 and the common difference is 3 3. Find the number of terms, n n, in the arithmetic … WebMar 30, 2024 · Answer: The AP series is 1,-1,-3,-5....Step-by-step explanation:Given : In an A.P, the sum of its first ten terms is -80 and sum of its next 10 terms is -280. ... 30.03.2024 Math Secondary School answered • expert verified In an A.P, the sum of its first ten terms is -80 and sum of its next 10 terms is -280. Find the A.P. See answers ...
WebLet a and d be the first term and the common difference of an A.P., respectively. n th term of an A.P. a n =a+(n-1)d. Sum of n terms of an A.P., S n =n/2[2a+(n-1)d]. We have: Sum of the … WebApr 7, 2024 · To find the sum of last ten terms, first we need to reverse the given A.P. According to the reverse A.P we have the first term a = 126, common difference (d) = -2, and number of terms (n) = 10. We will put these values in the formula of sum of AP. In this way we can find the sum of the last ten terms of the A.P. Complete step-by-step answer:
WebMar 30, 2024 · It is given that First term = a = 2 Also Sum of first five terms = 1/4 (Sum of next 5 terms) Sum of first five terms = 1/4 (Sum of 6th to 10th terms) Sum of first five terms = 1/4 ( 8 ( ("Sum of first 10 terms " @" Sum of first five terms" ))) S5 = 1/4 (S10 S5) 4S5 = S10 S5 4S5 + S5 = S10 5S5 = S10 Finding sum of first five terms We know that Sum …
WebMar 30, 2024 · Given : In an A.P, the sum of its first ten terms is -80 and sum of its next 10 terms is -280. To find : The A.P Solution : A.P series is a+a+d,a+2d,...... a is the first term , … order by descending pythonWebNov 16, 2015 · In an AP the first term is 2, the last term is 29 and sum of the terms is 155.Find the common difference of the AP. Asked by chittukala7 16 Nov, 2015, 06:26: PM ... find the sum of first 51 term of an AP whose second and third terms are 14 and 18 respectively. Asked by bkhaiwangkonyak 07 Mar, 2024, 04:35: PM. ANSWERED BY … order by descending power automateWebTo find the sum of arithmetic progression, we have to know the first term (a), the number of terms(n), and the common difference (d) between consecutive terms. Then substitute the … irc code gambling winningsWebFirst term = a. Last term = a 10. So, we know, a n = a + (n-1)d. For the 10 th term (n = 10), a 10 = a + (10 -1)d = a + 9d. So, here we can find the sum of the n terms of the given A.P., … irc collectiveWebSolution: Given, the sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. The sum of the first ten terms of the AP is 235. We have to find the sum of the first 20 terms. The sum of the first n terms of an AP is given by Sₙ = n/2 [2a + (n-1)d] When n = 10, S₁₀ = 10/2 [2a + (10 - 1)d] 235 = 5 [2a + 9d] irc comic booksWebAnswer: Let a be the first term and d be the common difference. 14th term = a + 13d = 100 27th term = a + 26d Sum of n terms = n/2 (2a+ (n-1)d) Sum of first 27 terms = (27/2)(2a+26d) Sum of first 27 terms = (27/2)(2)(a+13d) = 27(a+13d) = 27(100) [(a+13d)=100] = 2700 order by directionWebWe know the general form of GP for first five terms is given by: a, ar, ar 2, ar 3, ar 4 a = 10 ar = 10 × 3 = 30 ar 2 = 10 × 3 2 = 10 × 9 = 90 ar 3 = 10 × 3 3 = 270 ar 4 = 10 × 3 4 = 810 Therefore, the first five terms of GP with 10 as the first term and 3 as the common ratio are: 10, 30, 90, 270 and 810 order by distinct